x^2+12xy+20y^2=0

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Solution for x^2+12xy+20y^2=0 equation:


Simplifying
x2 + 12xy + 20y2 = 0

Reorder the terms:
12xy + x2 + 20y2 = 0

Solving
12xy + x2 + 20y2 = 0

Solving for variable 'x'.

Factor a trinomial.
(x + 2y)(x + 10y) = 0

Subproblem 1

Set the factor '(x + 2y)' equal to zero and attempt to solve: Simplifying x + 2y = 0 Solving x + 2y = 0 Move all terms containing x to the left, all other terms to the right. Add '-2y' to each side of the equation. x + 2y + -2y = 0 + -2y Combine like terms: 2y + -2y = 0 x + 0 = 0 + -2y x = 0 + -2y Remove the zero: x = -2y Simplifying x = -2y

Subproblem 2

Set the factor '(x + 10y)' equal to zero and attempt to solve: Simplifying x + 10y = 0 Solving x + 10y = 0 Move all terms containing x to the left, all other terms to the right. Add '-10y' to each side of the equation. x + 10y + -10y = 0 + -10y Combine like terms: 10y + -10y = 0 x + 0 = 0 + -10y x = 0 + -10y Remove the zero: x = -10y Simplifying x = -10y

Solution

x = {-2y, -10y}

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